🗊Презентация Tranlational equilibrium

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Слайды и текст этой презентации


Слайд 1





Translational Equilibrium
Описание слайда:
Translational Equilibrium

Слайд 2





Objectives
Describe with examples Newton’s three laws of motion.
Describe with examples the first condition for equilibrium.
Draw free-body diagrams for objects in translational equilibrium.
Apply the first condition for equilibrium to the solution of problems.
Описание слайда:
Objectives Describe with examples Newton’s three laws of motion. Describe with examples the first condition for equilibrium. Draw free-body diagrams for objects in translational equilibrium. Apply the first condition for equilibrium to the solution of problems.

Слайд 3





Newton’s First Law
Newton’s First Law: An object at rest or an object in motion at constant speed will remain at rest or at constant speed in the absence of a resultant force.
Описание слайда:
Newton’s First Law Newton’s First Law: An object at rest or an object in motion at constant speed will remain at rest or at constant speed in the absence of a resultant force.

Слайд 4





Newton’s Second Law:
Second Law:  Whenever a resultant force acts on an object, it produces an acceleration - an acceleration that is directly proportional to the force and inversely proportional to the mass.
Описание слайда:
Newton’s Second Law: Second Law: Whenever a resultant force acts on an object, it produces an acceleration - an acceleration that is directly proportional to the force and inversely proportional to the mass.

Слайд 5





Newton’s Third Law
To every action force there must be an equal and opposite reaction force.
Описание слайда:
Newton’s Third Law To every action force there must be an equal and opposite reaction force.

Слайд 6





Newton’s Third Law
Examples:
Описание слайда:
Newton’s Third Law Examples:

Слайд 7





Translational Equilibrium
An object is said to be in Translational Equilibrium if and only if there is no resultant force. 
This means that the sum of all acting forces is zero.
Описание слайда:
Translational Equilibrium An object is said to be in Translational Equilibrium if and only if there is no resultant force. This means that the sum of all acting forces is zero.

Слайд 8





Visualization of Forces
Описание слайда:
Visualization of Forces

Слайд 9





Visualization of Forces
Описание слайда:
Visualization of Forces

Слайд 10





Vector Sum of Forces
An object is said to be in Translational Equilibrium if and only if there is no resultant force. 
The vector sum of all forces acting on the ring is zero in this case.
Описание слайда:
Vector Sum of Forces An object is said to be in Translational Equilibrium if and only if there is no resultant force. The vector sum of all forces acting on the ring is zero in this case.

Слайд 11





Vector Force Diagram
Описание слайда:
Vector Force Diagram

Слайд 12





Look Again at Previous Arrangement
Описание слайда:
Look Again at Previous Arrangement

Слайд 13





Translational Equilibrium
The First Condition for Equilibrium is that there be no resultant force. 
This means that the sum of all acting forces is zero.
Описание слайда:
Translational Equilibrium The First Condition for Equilibrium is that there be no resultant force. This means that the sum of all acting forces is zero.

Слайд 14





Example 2. Find the tensions in ropes A and B for the arrangement shown.
Описание слайда:
Example 2. Find the tensions in ropes A and B for the arrangement shown.

Слайд 15





Example 2. Continued . . .
Описание слайда:
Example 2. Continued . . .

Слайд 16





Example 2. Continued . . .
Описание слайда:
Example 2. Continued . . .

Слайд 17





Example 2. Continued . . .
Описание слайда:
Example 2. Continued . . .

Слайд 18





Problem Solving Strategy
Описание слайда:
Problem Solving Strategy

Слайд 19





Example 3. Find Tension in Ropes A and B.
Описание слайда:
Example 3. Find Tension in Ropes A and B.

Слайд 20





Example 3. Find the tension in ropes A and B.
Описание слайда:
Example 3. Find the tension in ropes A and B.

Слайд 21





Example 3. Find the tension in ropes A and B.
Описание слайда:
Example 3. Find the tension in ropes A and B.

Слайд 22





Example 3 (Cont.) Find the tension in A and B.
Описание слайда:
Example 3 (Cont.) Find the tension in A and B.

Слайд 23





Example 3 (Cont.)   Find Tensions in A and B.
Описание слайда:
Example 3 (Cont.) Find Tensions in A and B.

Слайд 24





Example 3 (Cont.)   Find B with A = 200 N.
Описание слайда:
Example 3 (Cont.) Find B with A = 200 N.

Слайд 25





Example 4. Rotate axes for same example.
Описание слайда:
Example 4. Rotate axes for same example.

Слайд 26





Since A and B are perpendicular, we can find the new angle  from geometry.
Описание слайда:
Since A and B are perpendicular, we can find the new angle  from geometry.

Слайд 27


Tranlational equilibrium, слайд №27
Описание слайда:

Слайд 28





Example 4 (Cont.) We Now Solve for A and B:
Описание слайда:
Example 4 (Cont.) We Now Solve for A and B:

Слайд 29


Tranlational equilibrium, слайд №29
Описание слайда:

Слайд 30


Tranlational equilibrium, слайд №30
Описание слайда:

Слайд 31


Tranlational equilibrium, слайд №31
Описание слайда:

Слайд 32


Tranlational equilibrium, слайд №32
Описание слайда:

Слайд 33





Summary
Newton’s First Law: An object at rest or an object in motion at constant speed will remain at rest or at constant speed in the absence of a resultant force.
Описание слайда:
Summary Newton’s First Law: An object at rest or an object in motion at constant speed will remain at rest or at constant speed in the absence of a resultant force.

Слайд 34





Summary
Second Law:  Whenever a resultant force acts on an object, it produces an acceleration, an acceleration that is directly proportional to the force and inversely proportional to the mass.
Описание слайда:
Summary Second Law: Whenever a resultant force acts on an object, it produces an acceleration, an acceleration that is directly proportional to the force and inversely proportional to the mass.

Слайд 35





Summary
Third Law: To every action force there must be an equal and opposite reaction force.
Описание слайда:
Summary Third Law: To every action force there must be an equal and opposite reaction force.

Слайд 36





Problem Solving Strategy
Описание слайда:
Problem Solving Strategy

Слайд 37





Friction and Equilibrium
Описание слайда:
Friction and Equilibrium

Слайд 38





Objectives
Define and calculate the coefficients of kinetic and static friction, and give the relationship of friction to the normal force.
Apply the concepts of static and kinetic friction to problems involving constant motion or impending motion.
Описание слайда:
Objectives Define and calculate the coefficients of kinetic and static friction, and give the relationship of friction to the normal force. Apply the concepts of static and kinetic friction to problems involving constant motion or impending motion.

Слайд 39





Friction Forces
Описание слайда:
Friction Forces

Слайд 40





Friction and the Normal Force
Описание слайда:
Friction and the Normal Force

Слайд 41





Friction forces are independent of area.
Описание слайда:
Friction forces are independent of area.

Слайд 42





Friction forces are independent of speed.
Описание слайда:
Friction forces are independent of speed.

Слайд 43





The Static Friction Force
Описание слайда:
The Static Friction Force

Слайд 44





Constant or Impending Motion
Описание слайда:
Constant or Impending Motion

Слайд 45





Friction and Acceleration
Описание слайда:
Friction and Acceleration

Слайд 46





EXAMPLE 1:  If k = 0.3 and s = 0.5, what horizontal pull P is required to just start a 250-N block moving?
Описание слайда:
EXAMPLE 1: If k = 0.3 and s = 0.5, what horizontal pull P is required to just start a 250-N block moving?

Слайд 47





EXAMPLE 1(Cont.):  s = 0.5, W = 250 N. Find P  to overcome fs (max).  Static friction applies.
Описание слайда:
EXAMPLE 1(Cont.): s = 0.5, W = 250 N. Find P to overcome fs (max). Static friction applies.

Слайд 48





EXAMPLE 1(Cont.):  s = 0.5, W = 250 N. Find P  to overcome fs (max).  Now we know n = 250 N.
Описание слайда:
EXAMPLE 1(Cont.): s = 0.5, W = 250 N. Find P to overcome fs (max). Now we know n = 250 N.

Слайд 49





EXAMPLE 1(Cont.):  If k = 0.3 and s = 0.5, what horizontal pull P is required to move with constant speed?  (Overcoming kinetic friction)
Описание слайда:
EXAMPLE 1(Cont.): If k = 0.3 and s = 0.5, what horizontal pull P is required to move with constant speed? (Overcoming kinetic friction)

Слайд 50





The Normal Force and Weight
Описание слайда:
The Normal Force and Weight

Слайд 51





For Friction in Equilibrium:
Draw free-body diagram for each body.
Choose x or y-axis along motion or impending motion and choose direction of motion as positive.
Identify the normal force and write one of following: 
                fs = sn  or  fk = kn 
For equilibrium, we write for each axis:
		       Fx = 0      Fy = 0
Solve for unknown quantities.
Описание слайда:
For Friction in Equilibrium: Draw free-body diagram for each body. Choose x or y-axis along motion or impending motion and choose direction of motion as positive. Identify the normal force and write one of following: fs = sn or fk = kn For equilibrium, we write for each axis: Fx = 0 Fy = 0 Solve for unknown quantities.

Слайд 52





Example 2. A force of 60 N drags a 300-N block by a rope at an angle of 400 above the horizontal surface. If uk = 0.2, what force P will produce constant speed?
Описание слайда:
Example 2. A force of 60 N drags a 300-N block by a rope at an angle of 400 above the horizontal surface. If uk = 0.2, what force P will produce constant speed?

Слайд 53





Example 2 (Cont.). P = ?; W = 300 N; uk = 0.2.
Описание слайда:
Example 2 (Cont.). P = ?; W = 300 N; uk = 0.2.

Слайд 54





Example 2 (Cont.). P = ?; W = 300 N; uk = 0.2.
Описание слайда:
Example 2 (Cont.). P = ?; W = 300 N; uk = 0.2.

Слайд 55





Example 2 (Cont.). P = ?; W = 300 N; uk = 0.2.
Описание слайда:
Example 2 (Cont.). P = ?; W = 300 N; uk = 0.2.

Слайд 56





Example 2 (Cont.). P = ?; W = 300 N; uk = 0.2.
Описание слайда:
Example 2 (Cont.). P = ?; W = 300 N; uk = 0.2.

Слайд 57





Example 3: What push P up the incline is needed to move a 230-N block up the incline at constant speed if k = 0.3?
Описание слайда:
Example 3: What push P up the incline is needed to move a 230-N block up the incline at constant speed if k = 0.3?

Слайд 58





Example 3 (Cont.): Find P to give move up the incline (W = 230 N).
Описание слайда:
Example 3 (Cont.): Find P to give move up the incline (W = 230 N).

Слайд 59





Summary
Описание слайда:
Summary

Слайд 60





Summary: Important Points (Cont.)
Описание слайда:
Summary: Important Points (Cont.)

Слайд 61





Summary: Important Points (Cont.)
Описание слайда:
Summary: Important Points (Cont.)

Слайд 62





Summary
Описание слайда:
Summary

Слайд 63





Summary
Описание слайда:
Summary



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